The Roxboro - Milburnie Black 230-kV line has 80 MW and 60 MVAR flowing into Milburnie Substation. What is the power factor?

The Roxboro - Milburnie Black 230-kV line has 80 MW and 60 MVAR flowing into Milburnie Substation. What is the power factor?

• A. 80%
• B. 130%
• C. 60%
• D. 100%

Answer: (A)

To find the power factor, you need to understand the relationship between real power (measured in megawatts, MW) and reactive power (measured in megavolt-amperes reactive, MVAR). The power factor is defined as the ratio of real power to apparent power (which is the combination of both real power and reactive power). In this case, you have 80 MW of real power and 60 MVAR of reactive power. First, we calculate the apparent power using these values. The apparent power (S) can be calculated using the formula: \[ S = \sqrt{(P^2 + Q^2)} \] Where: - P = real power (in MW) = 80 MW - Q = reactive power (in MVAR) = 60 MVAR Calculating the apparent power: \[ S = \sqrt{(80^2 + 60^2)} \] \[ S = \sqrt{(6400 + 3600)} \] \[ S = \sqrt{10000} \] \[ S = 100 \text{ MVA} \] The power factor (PF) is then determined using the formula: \[ PF = \frac{P}{S

To find the power factor, you need to understand the relationship between real power (measured in megawatts, MW) and reactive power (measured in megavolt-amperes reactive, MVAR). The power factor is defined as the ratio of real power to apparent power (which is the combination of both real power and reactive power).

In this case, you have 80 MW of real power and 60 MVAR of reactive power. First, we calculate the apparent power using these values. The apparent power (S) can be calculated using the formula:

[ S = \sqrt{(P^2 + Q^2)} ]

Where:

• P = real power (in MW) = 80 MW

• Q = reactive power (in MVAR) = 60 MVAR

Calculating the apparent power:

[ S = \sqrt{(80^2 + 60^2)} ]

[ S = \sqrt{(6400 + 3600)} ]

[ S = \sqrt{10000} ]

[ S = 100 \text{ MVA} ]

The power factor (PF) is then determined using the formula:

[ PF = \frac{P}{S